200=5(2^x)

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Solution for 200=5(2^x) equation: 



200=5(2^x)

We move all terms to the left:

200-(5(2^x))=0

determiningTheFunctionDomain
-52^x+200=0

We move all terms containing x to the left, all other terms to the right

-52^x=-200

x=-200/1

x=-200

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